수학(Curiosity)
testing testing
hacking sorcerer
2025. 1. 5. 21:19
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Now expand:
∣xn−x~n∣2=(xn−u1(u1Txn))T(xn−u1(u1Txn))
$|x_n - \tilde{x}_n|^2 = \left( x_n - u_1 (u_1^T x_n) \right)^T \left( x_n - u_1 (u_1^T x_n) \right)$
Expanding the terms:
=xnTxn−2xnTu1(u1Txn)+(u1(u1Txn))T(u1(u1Txn))
$= x_n^T x_n - 2 x_n^T u_1 (u_1^T x_n) + \left( u_1 (u_1^T x_n) \right)^T \left( u_1 (u_1^T x_n) \right) $
For the last term, note that:
(u1(u1Txn))T(u1(u1Txn))=(u1Txn)2(u1Tu1)
$\left( u_1 (u_1^T x_n) \right)^T \left( u_1 (u_1^T x_n) \right) = (u_1^T x_n)^2 (u_1^T u_1)$
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